What Is The Equation Of A Circle Whose Center Is At The Origin And Whose Radius Is 16?
What Is The Equation Of A Circle Whose Center Is At The Origin And Whose Radius Is 16?. The equation of a circle whose center is at the origin and whose radius is 16 is x^2 + y^2 = 256. Start with the standard form:
(x, y) is an arbitrary point on the circumference of the circle. Here, centre is origin hence, h = 0 and k = 0, r = 16. See answers (2) best answer.
The Standard Equation Of A Circle With Center At (G, H) And.
Equation of circle with center at the origin. What is the equation of a circle whose center is at the origin and whose radius is 16? X 2 + y 2 = 16.
The Equation Of A Circle Whose Center Is At The Origin And Whose Radius Is 16 Is X^2 + Y^2 = 256.
Given center of circle is origin and radius is 16 units. X^2 + y^2 = 5 is the equation of a circle. General form of a circle.
X 2 + Y 2 = 4.
We are given to find the equation of a circle whose center is at the origin and whose radius is 16 units. See answers (2) best answer. Get answers chief of learnyverse.
(X, Y) Is An Arbitrary Point On The Circumference Of The Circle.
The equation of a circle whose center is at the origin and whose radius is 16 is x^2 + y^2 = 256. The equation of circle is (x−h)^2+ (y−k)^2 = r^2, where h,k is the center of circle and r is the. We know that equation of a circle with radius r and centre (h,k) is.
The Equation Of A Circle Whose Center Is At The Origin And Whose Radius Is 16 Is X^2 + Y^2 = 256
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